Here is some example data in a mysql table
a b distance
15 44 250
94 31 250
30 41 250
6 1 250
95 18 250
72 84 500
14 23 500
55 24 500
9
Use:
SELECT x.a,
x.b,
x.distance
FROM (SELECT t.a,
t.b,
t.distance
CASE
WHEN @distance != t.distance THEN @rownum := 1
ELSE @rownum := @rownum + 1
END AS rank,
@distance := t.distance
FROM TABLE t
JOIN (SELECT @rownum := 0, @distance := '') r
ORDER BY t.distance --important for resetting the rownum variable) x
WHERE x.rank <= 2
ORDER BY x.distance, x.a
I wonder if this will work?
SELECT
a,b,distance
FROM YourTable t2
WHERE ROW(a,b,distance) IN
(
SELECT a,b,distance FROM YourTable t1
WHERE t1.distance=t2.distance ORDER BY RAND() LIMIT 2
)
EDIT: unfortunately not. LIMIT is not supported in a subquery.
One way would be to use union. Like so:
(SELECT a, b, distance FROM table WHERE distance = 250 LIMIT 2 ORDER BY RAND())
UNION
(SELECT a, b, distance FROM table WHERE distance = 500 LIMIT 2 ORDER BY RAND())
...
ORDER BY distance
I can think of a way of getting one of each with one query using distinct =/, but like I said that would only bring you one.