PHP- Get file type by URL

Question

I want to get the file type (eg. image/gif) by URL using PHP.I had tried

Answer 1

the best way for my understanding

if (!function_exists('getUrlMimeType')) {
    function getUrlMimeType($url)
    {
        $buffer = file_get_contents($url);
        $finfo = new finfo(FILEINFO_MIME_TYPE);
        return $finfo->buffer($buffer);
    }
}

is to create function depend on finfo class

Answer 2

In the first example, you're getting a blank page because you're not doing anything with the return value from the function call. In the second example, you're getting a valid response. See the manual page for exif_imagetype() for a list of what the values mean.

Answer 3

3 is image type response for PNG image. See: http://php.net/manual/en/function.exif-imagetype.php

Answer 4

You are not going wrong anywhere. exif_imagetype returns the value of one of the image type constants: http://php.net/manual/en/image.constants.php

If you would like to convert this to an extension string, you could use a switch statement:

$typeString = null;
$typeInt = exif_imagetype($image_path);
switch($typeInt) {
  case IMG_GIF:
    $typeString = 'image/gif';
    break;
  case IMG_JPG:
    $typeString = 'image/jpg';
    break;
  case IMG_JPEG:
    $typeString = 'image/jpeg';
    break;
  case IMG_PNG:
    $typeString = 'image/png';
    break;
  case IMG_WBMP:
    $typeString = 'image/wbmp';
    break;
  case IMG_XPM:
    $typeString = 'image/xpm';
    break;
  default: 
    $typeString = 'unknown';
}

You may want to change the order to most to least frequently expected for better performance.

Answer 5

exif_imagetype returns the image type. The response, 3, indicates it is IMAGETYPE_PNG, the correct response.

Answer 6

<?php
 $image_path="http://fc04.deviantart.net/fs71/f/2010/227/4/6/PNG_Test_by_Destron23.png";
 echo exif_imagetype($image_path);
?>

It returned 3 because png response type as maciej said.

Try this to get like this image/png:

echo mime_content_type($image_path);

Try this:

$finfo = finfo_open(FILEINFO_MIME_TYPE); // return mime type ala mimetype extension   
echo finfo_file($finfo, $image_path) . "\n";
finfo_close($finfo);