You are adding the $_POST
array as the first element to $myarray
. If you wish to reference it, just do:
$myarray = $_POST;
However, this is probably not necessary, as you can just call it via $_POST
in your script.
$_POST is already an array, so you don't need to wrap array() around it.
Try this instead:
<?php
for ($i=0;$i<count($_POST['id']);$i++) {
echo "<p>".$_POST['id'][$i]."</p>";
echo "<p>".$_POST['value'][$i]."</p>";
echo "<hr />";
}
?>
NOTE: This works because your id
and value
arrays are symmetrical. If they had different numbers of elements then you'd need to take a different approach.
Why are you wrapping the $_POST
array in an array?
You can access your "id" and "value" arrays using the following
// assuming the appropriate isset() checks for $_POST['id'] and $_POST['value']
$ids = $_POST['id'];
$values = $_POST['value'];
foreach ($ids as $idx => $id) {
// ...
}
foreach ($values as $idx => $value) {
// ...
}
As you need to see the result for testing purpose. The simple and elegant solution is the below code.
echo "<pre>";
print_r($_POST);
echo "</pre>";
$_POST
is an array in itsself you don't need to make an array out of it. What you did is nest the $_POST
array inside a new array. This is why you print Array
.
Change it to:
foreach ($_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}