I have a compiler error in scala and I don\'t know what does it refer to:
Assume these declarations:
trait Abstract {
type MyType
}
trait AInner
trait
You can rewrite trait B
with (more later about your goal, which, I think, is a bit different)
trait B extends A {
type MyType <: BInner with AInner
}
And this makes total sense. A value of type B#MyType
can be seen as either a BInner
or a AInner
.
You don't need to repeat Abstract
because A
is already a subclass of Abstract
. You don't have to write override
as this is implicit for a type declaration. So the question is why A#MyType
is not working as AInner
?
Here is what the scala language spec says about volatile types.
3.6 Volatile Types
Type volatility approximates the possibility that a type parameter or abstract type instance of a type does not have any non-null values. As explained in (§3.1), a value member of a volatile type cannot appear in a path. A type is volatile if it falls into one of four categories: A compound type T1 with ... with Tn {R } is volatile if one of the following two conditions hold. 1. One of T2, ..., Tn is a type parameter or abstract type, or 2. T1 is an abstract type and and either the refinement R or a type Tj for j > 1 contributes an abstract member to the compound type, or 3. one of T1, ..., Tn is a singleton type. Here, a type S contributes an abstract member to a type T if S contains an abstract member that is also a member of T . A refinement R contributes an abstract member to a type T if R contains an abstract declaration which is also a member of T . A type designator is volatile if it is an alias of a volatile type, or if it designates a type parameter or abstract type that has a volatile type as its upper bound. A singleton type p.type is volatile, if the underlying type of path p is volatile. An existential type T forSome {Q } is volatile if T is volatile.
Other important item mentioned by the spec is about abstract type overriding:
Another restriction applies to abstract type members: An abstract type member with a volatile type (§3.6) as its upper bound may not override an abstract type member which does not have a volatile upper bound.
The compiler error is:
error: overriding type MyType in trait A with bounds <: AInner;
type MyType is a volatile type; cannot override a type with non-volatile upper bound
This is consistent with the spec. BInner with A#MyType
is volatile. Before that MyType
had a non-volatile as Any
.
The matter is that a type in the scala type system must have a unique meaning. An abstract type can be thought as a type which declaration is deferred to a subclass. Therefore there is no problem for declaring values of an abstract type when it is still abstract. On the other hand if we have a type like BInner with A#MyType
, this type may have several meaning. It is called volatile and it does not makes sense to have a non null value of this type, as it could have as many types as subclasses instantiating the MyType
abstract type. To simplify things, we could think of a volatile type as a type not being a subtype of Any
(and volatile as being a subtype Any
). We therefore have a contradiction that the compiler mentions.
Coming back to your goal, which you stated as
What I'm trying to achieve here(in trait B) is to further restrict the type MyType declared > in Abstract, so any value of type MyType must extend all the MyTypes in the mixin tree.
You can achieve this thanks to inner traits like this.
trait Abstract {
type MyType
}
trait B extends Abstract {
trait MyType {
def bMethod : Int
}
}
trait A extends B {
trait MyType extends super.MyType {
}
}
Well I hope this somewhat what you're looking for.
What is wrong with this?
trait B extends Abstract with A {
override type MyType <: BInner with AInner
}
In any realization of trait B
, MyType
will always be the same type as seen from trait A
, so upper-bounding it by itself does not make any sense.
If in the upper piece of code, it bothers you that you'll have to rewrite trait B
if you change the bound in trait A
, use:
trait A extends Abstract{
type ABound = AInner
type MyType <: AInner
}
trait B extends Abstract with A {
override type MyType <: BInner with ABound
}
Removing this check in the compiler lets us shine a light on the potential for unsoundness.
diff --git a/src/compiler/scala/tools/nsc/typechecker/Typers.scala b/src/compiler/scala/tools/nsc/typechecker/Typers.scala
index 37a7e3c..78a8959 100644
--- a/src/compiler/scala/tools/nsc/typechecker/Typers.scala
+++ b/src/compiler/scala/tools/nsc/typechecker/Typers.scala
@@ -5128,8 +5128,7 @@ trait Typers extends Adaptations with Tags {
def typedSelectFromTypeTree(tree: SelectFromTypeTree) = {
val qual1 = typedType(tree.qualifier, mode)
- if (qual1.tpe.isVolatile) TypeSelectionFromVolatileTypeError(tree, qual1)
- else typedSelect(tree, qual1, tree.name)
+ typedSelect(tree, qual1, tree.name)
}
def typedTypeBoundsTree(tree: TypeBoundsTree) = {
Then, running the code from a compiler test case for illegal type selection for volatile types:
scala> class A; class B extends A
defined class A
defined class B
scala> trait C {
| type U
| trait D { type T >: B <: A }
| val y: (D with U)#T = new B
| }
defined trait C
scala> class D extends C {
| trait E
| trait F { type T = E }
| type U = F
| def frob(arg : E) : E = arg
| frob(y)
| }
defined class D
scala> new D
java.lang.ClassCastException: B cannot be cast to D$E
As I understand it, the issue stems from the fact that Scala doesn't have true intersection types.
scala> type A = { type T = Int }
defined type alias A
scala> type B = { type T = String }
defined type alias B
scala> "": (A with B)#T
res16: String = ""
scala> 0: (A with B)#T
<console>:37: error: type mismatch;
found : Int(0)
required: String
0: (A with B)#T
^
This might change in the future, if the research into Dependent Object Types (DOT) bears fruit.