How can I get last inserted id using Hibernate

Question

I want to fetch the last inserted value\'s id in Hibernate.

After search:

Long lastId = ((Long) session.createSQLQuery(\"SELECT LAST_INSERT_ID()\").         


        

Answer 1

You can simply use save which returns a Serializable object that actually is the last insert id. Sample code:

Session session=this.getSessionFactory().getCurrentSession();
    int result = -1;
    try {
        Serializable ser = session.save(paper);
        if (ser != null) {
            result = (Integer) ser;
        }
    } catch (Exception e) {
        e.printStackTrace();
    }
    return result;

A testing run:

int result = paperService.save(paper);
    System.out.println("The id of the paper you just added is: "+result);

and here is the output:

The id of the paper you just added is: 3032

Answer 2

Error is pretty clear. It's returning BigInteger and not long

You have to assign it to a BigInteger. And get longValue() from it.

Answer 3

Since the return type of uniqueResult() is BigInteger and not Long, you should do it like this:

long lastId = session.createSQLQuery("SELECT LAST_INSERT_ID()")
                     .uniqueResult()  // this returns a BigInteger
                     .longValue();    // this will convert it to a long value

The method uniqueResult() only returns a BigInteger because of your query SELECT LAST_INSERT_ID().

Answer 4

public Integer save(Smartphones i) {
    int id = 0;
    Session session=HibernateUtil.getSessionFactory().openSession();
    Transaction trans=session.beginTransaction();
    try{
        session.save(i);   
        id=i.getId();
        trans.commit();     
    }
    catch(HibernateException he){}
    return id;
}