I have a byte buffer of unknown size, and I want to create a local struct variable pointing to the memory of the beginning of the buffer. Following what I\'d do in C, I trie
You can use methods on raw pointers and functions in std::ptr to directly read/write objects in place.
In your case:
fn main() {
let v: Vec<u8> = vec![1, 2, 3];
let s: MyStruct = unsafe { std::ptr::read(v.as_ptr() as *const _) };
println!("here is the struct: {:?}", s);
}
I would encourage you to wrap this in a reusable method and perform a length check on the source buffer before attempting the read.
I gave up on the transmute stuff. *mut
(raw pointers) in Rust are pretty similar to C pointers, so this was easy:
#[repr(C, packed)] // necessary
#[derive(Debug, Copy, Clone)] // not necessary
struct MyStruct {
foo: u16,
bar: u8,
}
fn main() {
let v: Vec<u8> = vec![1, 2, 3];
let buffer = v.as_slice();
let mut s_safe: Option<&MyStruct> = None;
let c_buf = buffer.as_ptr();
let s = c_buf as *mut MyStruct;
unsafe {
let ref s2 = *s;
s_safe = Some(s2);
}
println!("here is the struct: {:?}", s_safe.unwrap());
}
The unsafe
tag there is no joke, but the way I'm using this, I know my buffer is filled and take the proper precautions involving endianness later on.
If you don't want to copy the data to the struct but instead leave it in place, you can use slice::align_to. This creates a &MyStruct
instead:
#[repr(C, packed)]
#[derive(Debug, Copy, Clone)]
struct MyStruct {
foo: u16,
bar: u8,
}
fn main() {
let v = vec![1u8, 2, 3];
// I copied this code from Stack Overflow
// without understanding why this case is safe.
let (head, body, _tail) = unsafe { v.align_to::<MyStruct>() };
assert!(head.is_empty(), "Data was not aligned");
let my_struct = &body[0];
println!("{:?}", my_struct);
}
Here, it's safe to use align_to
to transmute some bytes to MyStruct
because we've used repr(C, packed)
and all of the types in MyStruct
can be any arbitrary bytes.
See also: