Returning From a Void Function in C++

Question

Consider the following snippet:

void Foo()
{
  // ...
}

void Bar()
{
  return Foo();
}

What is a legitimate reason to use the above in C++

Answer 1

Templates:

template <typename T, typename R>
R some_kind_of_wrapper(R (*func)(T), T t)
{
   /* Do something interesting to t */
   return func(t);
}

int func1(int i) { /* ... */ return i; }

void func2(const std::string& str) { /* ... */ }

int main()
{
   int i = some_kind_of_wrapper(&func1, 42);

   some_kind_of_wrapper(&func2, "Hello, World!");

   return 0;
}

Without being able to return void, the return func(t) in the template would not work when it was asked to wrap func2.