python increment ipaddress

Question

I would like to increment an ip address by a fixed value.

Precisely this is what I am trying to achieve, I have an ip address say, 192.168.0.3 and I wan

Answer 1

There's a module that makes this and other tasks very easy: pip install iptools.

In [1]: import iptools

In [3]: iptools.ip2long('127.0.0.1')
Out[3]: 2130706433

In [4]: p = iptools.ip2long('127.0.0.1') + 1
In [6]: iptools.long2ip(p)
Out[6]: '127.0.0.2'

Answer 2

In Python 3:

>>> import ipaddress
>>> ipaddress.ip_address('192.168.0.4')  # accept both IPv4 and IPv6 addresses
IPv4Address('192.168.0.4')
>>> int(_)
3232235524

>>> ipaddress.ip_address('192.168.0.4') + 256
IPv4Address('192.168.1.4')

In reverse:

>>> ipaddress.ip_address(3232235524)
IPv4Address('192.168.0.4')
>>> str(_)
'192.168.0.4'

>>> ipaddress.ip_address('192.168.0.4') -1
IPv4Address('192.168.0.3')

Python 2/3

You could use struct module to unpack the result of inet_aton() e.g.,

import struct, socket

# x.x.x.x string -> integer
ip2int = lambda ipstr: struct.unpack('!I', socket.inet_aton(ipstr))[0]
print(ip2int("192.168.0.4"))
# -> 3232235524

In reverse:

int2ip = lambda n: socket.inet_ntoa(struct.pack('!I', n))
print(int2ip(3232235525))
# -> 192.168.0.5