Rails 3 Float or decimal for GPS coordinates

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走了就别回头了 2020-12-31 09:00

I need to store GPS coordinates in a database. I\'ve heard that floats are less accurate than decimals. Is that true? If so, what reason is there to ever use floats?

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  • 2020-12-31 09:48

    As you can see in Paul's answer, it depends on your use-case.
    A float provides a precision of roughly 6 decimal digits.
    ±11 cm is quite acceptable for, say, an address. and if you're displaying addresses it's unlikely that you are going to do any arithmetical operations that will compound rounding errors.

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  • 2020-12-31 09:49

    If you want 100% accuracy with your decimals, then multiply by 10**n(where n is your desired precision), and store as integer.

    Float objects represent inexact real numbers using the native architecture's double-precision floating point representation.

    See:

    http://www.ruby-doc.org/core-1.9.3/Float.html
    
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  • 2020-12-31 09:53

    If you want more accurate GPS coordinates, then yes decimals are the way to go. You can create them with a migration like:

    create_table "models" do |t|
      t.decimal  "latitude", :precision => 15, :scale => 10, :default => 0.0
      t.decimal  "longitude", :precision => 15, :scale => 10, :default => 0.0
    end
    

    The reason people use floats is that they are usually precise enough for most use cases and use less space to store.

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  • 2020-12-31 09:54

    Since Earth equatorial circumference is around 40000 km and longitude spans 360 degrees, it follows that near the equator 1 degrees is equivalent to about 110 km.

    Thus:

    • 0 digit precision: ±110 km
    • 1 digit precision: ±11 km
    • 2 digit precision: ±1.1 km
    • 3 digit precision: ±110 m
    • 4 digit precision: ±11 m
    • 5 digit precision: ±1.1 m
    • 6 digit precision: ±11 cm
    • 7 digit precision: ±1.1 cm

    However, the closer you move to the Poles, the smaller the lenghts of the parallels becomes. For example near Paris, which has a latitude of 48 degrees, 1 degree is equivalent to cos(48) * 110 = 74 km.

    Thus:

    • 0 digit precision: ±74 km
    • 1 digit precision: ±7.4 km
    • 2 digit precision: ±0.74 km
    • 3 digit precision: ±74 m
    • 4 digit precision: ±7.4 m
    • 5 digit precision: ±0.74 m
    • 6 digit precision: ±7.4 cm
    • 7 digit precision: ±0.74 cm

    So, field of type DECIMAL(10,7) would be enough to satisfy you rather precise.

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