Default function that just returns the passed value?

Question

As a lazy developer, I like to use this trick to specify a default function:

template 

        

Answer 1

A way to deal with this is to have two different functions. I find quite sane not to use default parameters.

template <class Type, unsigned int Size, class Function>
void index(std::array<Type, Size> &x, Function&& f){
    for(unsigned int i = 0; i < Size; ++i) x[i] = f(i);
}

template<class Type, unsigned int Size>
void index(std::array<Type, Size> &x){
    return index(x, [](unsigned int i){return i;});                      // C++11 in this case
                //, [](auto&& e){return std::forward<decltype(e)>(e)};); // C++14 in a more general case
                //, std::identity); // C++20 in general
}

Answer 2

You can just build your own identity functor:

template <typename T>
class returnIdentifyFunctor
{
  public:
     auto operator ()(  T &&i ) -> decltype( std::forward<T>(i) )
    {
      return std::move(i);
    }
};

template <class Type, unsigned int Size, class Function = returnIdentifyFunctor<Type>>
void index(std::array<Type, Size> &x, Function&& f = Function() )
 {
    for (unsigned int i = 0; i < Size; ++i) {
            x[i] = f(i);
  }
}

Answer 3

There is no standard functor that does this, but it is easy enough to write (though the exact form is up for some dispute):

struct identity {
    template<typename U>
    constexpr auto operator()(U&& v) const noexcept
        -> decltype(std::forward<U>(v))
    {
        return std::forward<U>(v);
    }
};

This can be used as follows:

template <class Type, std::size_t Size, class Function = identity>
void index(std::array<Type, Size> &x, Function&& f = Function())
{
    for (unsigned int i = 0; i < Size; ++i) {
        x[i] = f(i);
    }
}

Answer 4

This is called the identity function. Unfortunately, it is not part of the C++ standard, but you can easily build one yourself.

---

If you happen to use g++, you can activate its extensions with -std=gnu++11 and then

#include <array>
#include <ext/functional>

template <class Type, std::size_t Size, class Function = __gnu_cxx::identity<Type> >
void index(std::array<Type, Size> &x, Function&& f = Function())
{
    for (unsigned int i = 0; i < Size; ++i) {
        x[i] = f(i);
    }
}

---

Maybe it will be available in C++20, see std::identity. Until then you may look at boost's version at boost::compute::identity.

Answer 5

boost::phoenix offers a complete functional toolbox, here 'arg1' is the ident to identity ;-)

#include <boost/phoenix/core.hpp>

template <class X, class Function = decltype(boost::phoenix::arg_names::arg1)>
void index(X &x, Function f = Function()) {
    for (std::size_t i = 0; i < x.size(); ++i) {
            x[i] = f(i);
  }
}

Answer 6

There is the following variant with boost:

template <class Type, unsigned int Size, class Function = boost::function<Type(Type)>>
void index(std::array<Type, Size> &x, Function&& f = boost::bind(std::plus<Type>(), 0, _1))