MySQL check if an IP-address is in range?

Question

I have a table that contains two columns ipStart and ipEnd

These two fields contain a range of ip address. For example:

`ip         


        

Answer 1

Try this

SELECT *
FROM TABLE_NAME
WHERE (INET_ATON("193.235.19.255") BETWEEN INET_ATON(ipStart) AND INET_ATON(ipEnd));

Answer 2

To explain converting an ip address to a number which a few answers have relied on (and which I agree with).

The ip address needs to be treated as one 32 bit number rather than 4 8 bit numbers

For example the ip address

193.235.18.0

converted to binary is:-

11000001.11101011.00010010.00000000

Which you translate into (ie, take the dots out):-

11000001111010110001001000000000

Working that out you get:-

1 * 2147483648 = 2147483648 
1 * 1073741824 = 1073741824 
0 * 536870912 = 0
0 * 268435456 = 0
0 * 134217728 = 0
0 * 67108864 = 0
0 * 33554432 = 0
1 * 16777216 = 16777216 
1 * 8388608 = 8388608 
1 * 4194304 = 4194304 
1 * 2097152 = 2097152 
0 * 1048576 = 0
1 * 524288 = 524288 
0 * 262144 = 0
1 * 131072 = 131072 
1 * 65536 = 65536 
0 * 32768 = 0
0 * 16384 = 0
0 * 8192 = 0
1 * 4096 = 4096 
0 * 2048 = 0
0 * 1024 = 0
1 * 512 = 512 
0 * 256 = 0
0 * 128 = 0
0 * 64 = 0
0 * 32 = 0
0 * 16 = 0
0 * 8 = 0
0 * 4 = 0
0 * 2 = 0
0 * 1 = 0

Adding those together you get 3253408256

You an short cut that a bit by treating the original IP address as a base 256 number. So you have 0 units, 18 of 256s, 235 of 65536 (ie, 256 * 256) and 193 of (ie, 256 * 256 * 256)

0 * 1 + 18 * 256 + 235 * 256 * 256 + 193 * 256 * 256 * 256

INET_ATON function that is mentioned does this for you.