I\'m not looking for solution, I\'m looking for a better solution or just a different way to do this by using some other kind of list comprehension or something else.
<Using itertools.product():
from itertools import product
coordinates = list(product(xrange(width), xrange(height)))
UPDATED: Added @F.J. answer in the benchmark
The first implementation is the most pythonic way, and seems to be the fastest, too.
Using 1000
for each, width and height, I register execution-times of
0.35903096199s
0.461946964264s
0.625234127045s
@F.J 0.27s
So yeah, his answer is the best.
The first solution is elegant, but you could also use a generator expression instead of a list comprehension:
((x, y) for x in range(width) for y in range(height))
This might be more efficient, depending on what you're doing with the data, because it generates the values on the fly and doesn't store them anywhere.
This also produces a generator; in either case, you have to use list
to convert the data to a list.
>>> list(itertools.product(range(5), range(5)))
[(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (1, 0), (1, 1), (1, 2),
(1, 3), (1, 4), (2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (3, 0),
(3, 1), (3, 2), (3, 3), (3, 4), (4, 0), (4, 1), (4, 2), (4, 3), (4, 4)]
Note that if you're using Python 2, you should probably use xrange
, but in Python 3, range
is fine.