Convert 12 hour into 24 hour times

Question

I\'m trying to convert times from 12 hour times into 24 hour times...

Automatic Example times:

06:35  ## Morning
11:35  ## Morning (If m2 is anywhe         


        

Answer 1

time = raw_input().strip() # input format in hh:mm:ssAM/PM
t_splt = time.split(':')
if t_splt[2][2:] == 'PM' and t_splt[0] != '12':
    t_splt[0] = str(12+ int(t_splt[0]))
elif int(t_splt[0])==12 and t_splt[2][2:] == 'AM':
    t_splt[0] = '00'
t_splt[2] = t_splt[2][:2]
print ':'.join(t_splt)

Answer 2

Instead of using "H" for hour indication use "I" as described in the example bellow:

from datetime import *
m2 = 'Dec 14 2018 1:07PM'
m2 = datetime.strptime(m2, '%b %d %Y %I:%M%p')
print(m2)

Please check this link

Answer 3

You need to specify that you mean PM instead of AM.

>>> from datetime import *
>>> m2 = '1:35 PM'
>>> m2 = datetime.strptime(m2, '%I:%M %p')
>>> print(m2)
1900-01-01 13:35:00

Answer 4

If date is in this format (HH:MM:SSPM/AM) the following code is effective :

a=''
def timeConversion(s):
   if s[-2:] == "AM" :
      if s[:2] == '12':
          a = str('00' + s[2:8])
      else:
          a = s[:-2]
   else:
      if s[:2] == '12':
          a = s[:-2]
      else:
          a = str(int(s[:2]) + 12) + s[2:8]
   return a


s = '11:05:45AM'
result = timeConversion(s)
print(result)

Answer 5

the most basic way is:

t_from_str_12h = datetime.datetime.strptime(s, "%I:%M:%S%p")
str_24h =  t_from_str.strftime("%H:%M:%S")

Answer 6

Try this