How to to filter dict to select only keys greater than a value? [duplicate]

Answer 1

List comprehension seems to be what you seek but with a list of elements as opposed to keys:

a = {5:"djdj", 6:"8899", 7:"998kdj"}
[a[elem] for elem in a if elem >= 6]  #should give you "['8866', '998kd']"

Answer 2

[v for k,v in mydict.items() if k >= 6]

Answer 3

[ mydict[k] for k in filter(lambda x : x > 6, mydict) ]

Answer 4

To get a dictionary right away: (works in both python 2 and 3)

dict( (k,v) for k,v in mydict.items() if k >= 6 )

Answer 5

You can use a list comprehension:

mydict = {5:"djdj", 6:"8899", 7:"998kdj"}
print [k for k in mydict if k >= 6]  # prints "[6, 7]"
print dict([(k, mydict[k]) for k in mydict if k >= 6])  # prints "{6:"8899", 7:"998kdj"}"

Answer 6

It can be done with filter too.

In [9]: data = {5:"djdj", 6:"8899", 7:"998kdj"}

In [10]: dict(filter(lambda x: x[0] > 5, data.items()))
Out[10]: {6: '8899', 7: '998kdj'}