Bash script: difference in minutes between two times

Question

I have two time strings; eg. \"09:11\" and \"17:22\" on the same day (format is hh:mm). How do I calculate the time difference in minutes between these two?

Can the

Answer 1

I was looking for a solution with seconds. Found here: How to calculate time difference in bash script?

#!/bin/bash
string1="10:33:56"
string2="10:36:10"
StartDate=$(date -u -d "$string1" +"%s")
FinalDate=$(date -u -d "$string2" +"%s")
date -u -d "0 $FinalDate sec - $StartDate sec" +"%H:%M:%S"

Here I have added seconds to Gilles' solution:

function countTimeDiff() {
    timeA=$1 # 09:59:35
    timeB=$2 # 17:32:55

    # feeding variables by using read and splitting with IFS
    IFS=: read ah am as <<< "$timeA"
    IFS=: read bh bm bs <<< "$timeB"

    # Convert hours to minutes.
    # The 10# is there to avoid errors with leading zeros
    # by telling bash that we use base 10
    secondsA=$((10#$ah*60*60 + 10#$am*60 + 10#$as))
    secondsB=$((10#$bh*60*60 + 10#$bm*60 + 10#$bs))
    DIFF_SEC=$((secondsB - secondsA))
    echo "The difference is $DIFF_SEC seconds.";

    SEC=$(($DIFF_SEC%60))
    MIN=$((($DIFF_SEC-$SEC)%3600/60))
    HRS=$((($DIFF_SEC-$MIN*60)/3600))
    TIME_DIFF="$HRS:$MIN:$SEC";
    echo $TIME_DIFF;
}

Answer 2

Here is how I did it:

START=$(date +%s);
sleep 1; # Your stuff
END=$(date +%s);
echo $((END-START)) | awk '{printf "%d:%02d:%02d", $1/3600, ($1/60)%60, $1%60}'

Really simple, take the number of seconds at the start, then take the number of seconds at the end, and print the difference in minutes:seconds.

Answer 3

STARTTIME=$(date +%s)

YOUR CODES :

ENDTIME=$(date +%s)
secs=$(($ENDTIME - $STARTTIME))
printf 'Elapsed Time %dh:%dm:%ds\n' $(($secs/3600)) $(($secs%3600/60)) $(($secs%60)) 

Answer 4

I would convert the dates to UNIX timestamps; you can subtract to get the difference in seconds, then divide by 60:

#!/bin/bash

MPHR=60    # Minutes per hour.

CURRENT=$(date +%s -d '2007-09-01 17:30:24')
TARGET=$(date +%s -d'2007-12-25 12:30:00')

MINUTES=$(( ($TARGET - $CURRENT) / $MPHR ))

Answer 5

@Dorian
If you just want to know how long a program took to run: time, man, man time!

Trivial example:

jonathan@Odin:~$ time sleep 1

real    0m1.001s
user    0m0.000s
sys     0m0.000s

OK, it doesn't give the result in seconds, but you can make it do so with a format string, or more simply with the POSIX compliance option:

jonathan@Odin:~$ time -p sleep 20
real 20.00
user 0.00
sys 0.00

Answer 6

MPHR=60
CURRENT=09:11
TARGET=17:22
echo $(( ( 10#${TARGET:0:2} - 10#${CURRENT:0:2} ) * MPHR + 10#${TARGET:4} - 10#${CURRENT:4} ))