Get the difference between two dates both In Months and days in sql

Question

I need to get the difference between two dates say if the difference is 84 days, I should probably have output as 2 months and 14 days, the code I have just gives the totals

Answer 1

Find out Year - Month- Day between two Days in Orale Sql

---

select 
trunc(trunc(months_between(To_date('20120101', 'YYYYMMDD'),to_date('19910228','YYYYMMDD')))/12) years ,
trunc(months_between(To_date('20120101', 'YYYYMMDD'),to_date('19910228','YYYYMMDD'))) 
-
(trunc(trunc(months_between(To_date('20120101', 'YYYYMMDD'),to_date('19910228','YYYYMMDD')))/12))*12
months,
             round(To_date('20120101', 'YYYYMMDD')-add_months(to_date('19910228','YYYYMMDD'),
                           trunc(months_between(To_date('20120101', 'YYYYMMDD'),to_date('19910228','YYYYMMDD'))))) days
        from dual;

Answer 2

Updated for correctness. Originally answered by @jen.

with DATES as (
   select TO_DATE('20120101', 'YYYYMMDD') as Date1,
          TO_DATE('20120325', 'YYYYMMDD') as Date2
   from DUAL union all
   select TO_DATE('20120101', 'YYYYMMDD') as Date1,
          TO_DATE('20130101', 'YYYYMMDD') as Date2
   from DUAL union all
   select TO_DATE('20120101', 'YYYYMMDD') as Date1,
          TO_DATE('20120101', 'YYYYMMDD') as Date2
   from DUAL union all
   select TO_DATE('20130228', 'YYYYMMDD') as Date1,
          TO_DATE('20130301', 'YYYYMMDD') as Date2
   from DUAL union all
   select TO_DATE('20130228', 'YYYYMMDD') as Date1,
          TO_DATE('20130401', 'YYYYMMDD') as Date2
   from DUAL
), MONTHS_BTW as (
   select Date1, Date2,
          MONTHS_BETWEEN(Date2, Date1) as NumOfMonths
   from DATES
)
select TO_CHAR(Date1, 'MON DD YYYY') as Date_1,
       TO_CHAR(Date2, 'MON DD YYYY') as Date_2,
       NumOfMonths as Num_Of_Months,
       TRUNC(NumOfMonths) as "Month(s)",
       ADD_MONTHS(Date2, - TRUNC(NumOfMonths)) - Date1 as "Day(s)"
from MONTHS_BTW;

SQLFiddle Demo :

    +--------------+--------------+-----------------+-----------+--------+
    |   DATE_1     |   DATE_2     | NUM_OF_MONTHS   | MONTH(S)  | DAY(S) |
    +--------------+--------------+-----------------+-----------+--------+
    | JAN 01 2012  | MAR 25 2012  | 2.774193548387  |        2  |     24 |
    | JAN 01 2012  | JAN 01 2013  | 12              |       12  |      0 |
    | JAN 01 2012  | JAN 01 2012  | 0               |        0  |      0 |
    | FEB 28 2013  | MAR 01 2013  | 0.129032258065  |        0  |      1 |
    | FEB 28 2013  | APR 01 2013  | 1.129032258065  |        1  |      1 |
    +--------------+--------------+-----------------+-----------+--------+

Notice, how for the last two dates, Oracle reports the decimal part of months (which gives days) incorrectly. 0.1290 corresponds to exactly 4 days with Oracle considering 31 days in a month (for both March and April).

Answer 3

is this what you've ment ?

select trunc(months_between(To_date('20120325', 'YYYYMMDD'),to_date('20120101','YYYYMMDD'))) months,
             round(To_date('20120325', 'YYYYMMDD')-add_months(to_date('20120101','YYYYMMDD'),
                           trunc(months_between(To_date('20120325', 'YYYYMMDD'),to_date('20120101','YYYYMMDD'))))) days
        from dual;

Answer 4

Here I'm just doing the difference between today, and a CREATED_DATE DATE field in a table, which obviously is a date in the past:

SELECT  
((FLOOR(ABS(MONTHS_BETWEEN(CREATED_DATE, SYSDATE))) / 12) * 12) || ' months, '  AS MONTHS,
-- we take total days - years(as days) - months(as days) to get remaining days
FLOOR((SYSDATE - CREATED_DATE) -      -- total days
(FLOOR((SYSDATE - CREATED_DATE)/365)*12)*(365/12) -      -- years, as days
-- this is total months - years (as months), to get number of months, 
-- then multiplied by 30.416667 to get months as days (and remove it from total days)
FLOOR(((SYSDATE - CREATED_DATE)/365)*12 - (FLOOR((SYSDATE - CREATED_DATE)/365)*12)) * (365/12))
|| ' days ' AS DAYS 
FROM MyTable

I use (365/12), or 30.416667, as my conversion factor because I'm using total days and removing years and months (as days) to get the remainder number of days. It was good enough for my purposes, anyway.

Answer 5

MsSql Syntax : DATEDIFF ( datepart , startdate , enddate )

Oracle: This will returns number of days

    select
  round(Second_date - First_date)  as Diff_InDays,round ((Second_date - First_date) / (30),1)  as Diff_InMonths,round ((Second_date - First_date) * (60*24),2)  as TimeIn_Minitues
from
  (
  select
    to_date('01/01/2012 01:30:00 PM','mm/dd/yyyy hh:mi:ss am') as First_date
   ,to_date('05/02/2012 01:35:00 PM','mm/dd/yyyy HH:MI:SS AM') as Second_date
  from
    dual
  ) result;

Demo : http://sqlfiddle.com/#!4/c26e8/36

Answer 6

select 
  dt1, dt2,
  trunc( months_between(dt2,dt1) ) mths, 
  dt2 - add_months( dt1, trunc(months_between(dt2,dt1)) ) days
from
(
    select date '2012-01-01' dt1, date '2012-03-25' dt2 from dual union all
    select date '2012-01-01' dt1, date '2013-01-01' dt2 from dual union all
    select date '2012-01-01' dt1, date '2012-01-01' dt2 from dual union all
    select date '2012-02-28' dt1, date '2012-03-01' dt2 from dual union all
    select date '2013-02-28' dt1, date '2013-03-01' dt2 from dual union all
    select date '2013-02-28' dt1, date '2013-04-01' dt2 from dual union all
    select trunc(sysdate-1)  dt1, sysdate               from dual
) sample_data

Results:

|                        DT1 |                       DT2 | MTHS |     DAYS |
----------------------------------------------------------------------------
|  January, 01 2012 00:00:00 |   March, 25 2012 00:00:00 |    2 |       24 |
|  January, 01 2012 00:00:00 | January, 01 2013 00:00:00 |   12 |        0 |
|  January, 01 2012 00:00:00 | January, 01 2012 00:00:00 |    0 |        0 |
| February, 28 2012 00:00:00 |   March, 01 2012 00:00:00 |    0 |        2 |
| February, 28 2013 00:00:00 |   March, 01 2013 00:00:00 |    0 |        1 |
| February, 28 2013 00:00:00 |   April, 01 2013 00:00:00 |    1 |        1 |
|   August, 14 2013 00:00:00 |  August, 15 2013 05:47:26 |    0 | 1.241273 |

Link to test: SQLFiddle