Forcing an item to remain in place in a jQuery UI Sortable list

Question

I\'ve set up a jQuery sortable list but I need to be able to keep some items in the sortable \'fixed\' in place and for the other items to sort around them. I thought that t

Answer 1

I managed to do this by modifying jitters code a bit, and attach it to the "change" event rather than the "stop". I did it by looking how the index changes when dragging an item around and set up some conditionals. It also works with multiple fixed elements. The "lockto" variable defines the positon of the fixed element, and the fixed element should be in this position initially. You could probably rewrite this and wrap it in a function so you don't need to manually set the "lockto" variable for all fixed elements.

$("#sortable").sortable({
    "cancel":"li.static",
    "change":function(event,ui) {
        var lockto = 6;
        var thisindex = $(ui.helper).index(fixed);         
        var fixed = $("#static-"+lockto);           
        var index = $("#sortable li").index(fixed);
        var targetindex = lockto+1;
        if(index !== targetindex) {         
            if(index > targetindex ) {
                fixed.prev().insertAfter(fixed); //move it up by one position
            } else if(index==(targetindex-1) && thisindex>targetindex) {
                //don't move it at all
            } else {
                fixed.next().insertBefore(fixed); //move it down by one position
            }
        } else if(index==targetindex && thisindex>targetindex) {
            fixed.prev().insertAfter(fixed); //move it up by one position
        }       
    }
});

Answer 2

This is non trivial I guess. For your example it's still feasible with a little work (a generic solution would be a bit harder)

Check http://jsbin.com/etubi/2 for a demo (http://jsbin.com/etubi/2/edit for the code)

$("#sortable").sortable({
    cancel: "li.fixed", //exclude fixed ones
    stop:function(event, ui) {
        //nothing to do for #f0 as you can't sort anything above it
        var f5 = $("#f5");
        var indf5 = $("#sortable li").index(f5);
        //if f5 not in right position -> swap position
        if(indf5 !== 5) {
            if(indf5 > 5) {
                f5.prev().insertAfter(f5); //move it up by one position
            } else {
                f5.next().insertBefore(f5); //move it down by one position
            }
        }
    }
});

Answer 3

Wish I had seen this question before I posted mine and did all that Sortable research. This could have been a good starting point. Anyway, here's JQuery Sortable set item to an index programmatically a generic solution to this problem.