Random sample of rows from subset of an R dataframe [duplicate]

Answer 1

This is now simpler with the enhanced version of sample in my package:

library(devtools); install_github('kimisc', 'krlmlr')

library(kimisc)
sample.rows(subset(mydf, gender == "F"), 3)

See also this related answer for more detail.

Answer 2

You say I cannot use the obvious:

sample(mydf[mydf$gender == "F", ], 3)

but you could write your own function for doing it:

sample.df <- function(df, n) df[sample(nrow(df), n), , drop = FALSE]

then run it on your subset selection:

sample.df(mydf[mydf$gender == "F", ], 3)
#   gender age
# 5      F  31
# 4      F  29
# 1      F  23

(Personally I find sample.df(subset(mydf, gender == "F"), 3) easier to read.)

Answer 3

Your convoluted way is pretty much how to do it - I think all the answers will be variations on that theme.

For example, I like to generate the mydf$gender=="F" indices first:

idx <- which(mydf$gender=="F")

Then I sample from that:

mydf[ sample(idx,3), ]

So in one line (although, you reduce the absurd number of brackets and possibly make your code easier to understand by having multiple lines):

mydf[ sample( which(mydf$gender=='F'), 3 ), ]

While the "wheee I'm a hacker!" part of me prefers the one-liner, the sensible part of me says that even though the two-liner is two lines, it is much more understandable - it's just your choice.