Get Uploaded File's Original Name

Question

$request = $event->getRequest();
print_r($request->files);die;

gives me

Symfony\\Component\\HttpFoundation\\FileBag Object
(
         


        

Answer 1

When you upload files you get UploadFile (API link) objects (basically the wrappers of array).

$this->getRequest()->files[0]->getClientOriginalName();

Can't try this now but you might need to do this instead:

$this->getRequest()->files['name_of_file_field_in_post']->getClientOriginalName();

where you would replace name_of_file_field_in_post with your form field's name.

Answer 2

I'm using symfony 4,

I wanted to get the files original name. What worked for me is:

$form = $this->createForm(SomeType::class, $object);

if($form->isSubmitted() && $form->isValid()) {

    $fileName = $object->getImage()->getClientOriginalName();

}

In my case getImage() is the getter for the name of the file upload field. So that would change to your relevant getter function for the file upload field.

Answer 3

2015 Update:

$request->files->get('your-file-name')->getClientOriginalName();

your-file-name for me was just file.

This will probably help too: https://github.com/1up-lab/OneupUploaderBundle/issues/21

Answer 4

This wound up working for me, I guess the OneUp Class handles it a bit differently

use Oneup\UploaderBundle\Event\PostPersistEvent;
class UploadListener
{
     public function onUpload(PostPersistEvent $event)
    {

        $request = $event->getRequest();
        $original_filename = $request->files->get('blueimp')->getClientOriginalName();
     }
}

Relevent Frontend

<input id="fileupload" type="file" name="blueimp" data-url="{{ oneup_uploader_endpoint('images') }}" multiple />