How to validate xml with dtd using java?

Question

I have following xml file:

 E-001
 Vinod  
&l         


        

Answer 1

There are three things you should do:

• Associate the source XML document with its DTD using a doctype declaration after the XML declaration:

  <!DOCTYPE Employee SYSTEM "employee.dtd">
  

  Note: The DOCTYPE root must match the root element in the source XML.

• setValidating to true on the DocumentBuilderFactory

• Provide an org.xml.sax.ErrorHandler instance to the DocumentBuilder using setErrorHandler

Here's a complete example:

DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setValidating(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
builder.setErrorHandler(new ErrorHandler() {
    @Override
    public void error(SAXParseException exception) throws SAXException {
        // do something more useful in each of these handlers
        exception.printStackTrace();
    }
    @Override
    public void fatalError(SAXParseException exception) throws SAXException {
        exception.printStackTrace();
    }

    @Override
    public void warning(SAXParseException exception) throws SAXException {
        exception.printStackTrace();
    }
});
Document doc = builder.parse("employee.xml");

Source document:

<?xml version="1.0"?>
<!DOCTYPE Employee SYSTEM "employee.dtd">
<Employee>
    <Emp_Id> E-001</Emp_Id>
    <Emp_Name> Vinod </Emp_Name>
    <Emp_E-mail> Vinod1@yahoo.com </Emp_E-mail>
</Employee>

Answer 2

You just need to read the files and report the exceptions, if any. Here is a SAX parser example you can rely upon.

In order to validate your XML and DTD you just need to setValidating:

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    dbf.setValidating(true); // since the default value is false

Also declare the DTD usage in your XML file:

<?xml version="1.0"?>
<!DOCTYPE Employee SYSTEM "employee.dtd">
<Employee>