Returning multiple rows from querying XML column in SQL Server 2008

Question

I have a table RDCAlerts with the following data in a column of type XML called AliasesValue:

Answer 1

Look at the .nodes() method in Books Online:

DECLARE @r TABLE (AliasesValue XML)
INSERT INTO @r 
SELECT '<aliases>   <alias>     <aliasType>AKA</aliasType>     <aliasName>Pramod Singh</aliasName>   </alias>   <alias>     <aliasType>AKA</aliasType>     <aliasName>Bijoy Bora</aliasName>   </alias> </aliases> '


SELECT c.query('data(aliasType)'), c.query('data(aliasName)')
FROM @r r CROSS APPLY AliasesValue.nodes('aliases/alias') x(c)

Answer 2

You need to use the CROSS APPLY statement along with the .nodes() function to get multiple rows returned.

select 
    a.alias.value('(aliasType/text())[1]', 'varchar(20)') as 'aliasType', 
    a.alias.value('(aliasName/text())[1]', 'varchar(20)') as 'aliasName' 
from 
    RDCAlerts r
    cross apply r.AliasesValue.nodes('/aliases/alias') a(alias)