Groovy custom sort a map by value

Question

I have a map such as

m=[
     \"james\":\"silly boy\",
     \"janny\":\"Crazy girl\",
     \"jimmy\":\"funny man\",
     \"georges\":\"massive fella\"
];


        

Answer 1

BTW, here is code which is showing different sorting with and without toLowerCase():

Map m =[ james  :"silly boy",
         janny  :"crazy girl",
         jimmy  :"Funny man",
         georges:"massive fella" ]
Map sorted = m.sort { a, b -> a.value <=> b.value }
println sorted
sorted = m.sort { a, b -> a.value.toLowerCase() <=> b.value.toLowerCase() }
println sorted

And wll print:

[jimmy:Funny man, janny:crazy girl, georges:massive fella, james:silly boy]
[janny:crazy girl, jimmy:Funny man, georges:massive fella, james:silly boy]

Answer 2

To sort with case insensitive, use

m.sort { it.value.toLowerCase() }

Answer 3

If somebody is looking for how to make it work in the Jenkins pipeline script, you will have to create a separate method with @NonCPS annotation for that:

@NonCPS
def getSorted(def mapSizeMap){
    mapSizeMap.sort(){ a, b -> b.value <=> a.value }
}

And then call it from the pipeline script.

def sortedMapZoneMap = getSorted(mapZonesMap)

You can of course apply "case sensitive" logic on top.

Answer 4

Assuming you mean you want to sort on value, you can just do:

Map m =[ james  :"silly boy",
         janny  :"Crazy girl",
         jimmy  :"funny man",
         georges:"massive fella" ]

Map sorted = m.sort { a, b -> a.value <=> b.value }