Django error: got multiple values for keyword argument

Question

I get the following error when instantiating a Django form with a the constructor overriden:

__init__() got multiple values for keyword argument \'collection         


        

Answer 1

Daniel Roseman's solution is to handle a mixture of *args and **kwargs better, but gruszczy's explanation is the correct one:

You have defined CreateCollectionForm.__init__ with this signature:

def __init__(self, collection_type, user=None, parent=None, *args, **kwargs)

And you are then calling it like this:

form = CreateCollectionForm(
    request.POST, 
    collection_type=collection_type, 
    parent=parent, 
    user=request.user
)

self is assigned implicitly during the call. After that, Python sees only one positional argument: request.POST, which is assigned as collection_type, the first parameter. Then, the keyword arguments are processed, and when Python sees another keyword argument names collection_type, then it has to throw a TypeError.

Daniel's solution is a good one, by removing all named parameters, it is much easier to handle things like this, and to pass them up through super() to higher-level constructors. Alternately, you need to make the post dictionary the first formal parameter to your __init__ method, and pass it up to the superclass.

Answer 2

It's pretty simple: you pass request.POST and only afterward you put argument for collection_type. Onto what request.POST will be put? There is not place for that. Watch this:

In [8]: class A:
   ...:     def __init__(self, a, *args):
   ...:         print a, args
   ...:         
   ...:         

In [9]: A(None, a=None)
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)

/home/gruszczy/Programy/logbuilder/<ipython console> in <module>()

TypeError: __init__() got multiple values for keyword argument 'a'

Move request.POST somewhere else in the call, but remember, that named arguments come after the ones, that aren't.

Answer 3

You're passing the collection_type argument in as a keyword argument, because you specifically say collection_type=collection_type in your call to the form constructor. So Python includes it within the kwargs dictionary - but because you have also declared it as a positional argument in that function's definition, it attempts to pass it twice, hence the error.

However, what you're trying to do will never work. You can't have user=None, parent=None before the *args dictionary, as those are already kwargs, and args must always come before kwargs. The way to fix it is to drop the explicit definition of collection_type, user and parent, and extract them from kwargs within the function:

def __init__(self, *args, **kwargs):
    collection_type = kwargs.pop('collection_type', None)
    user = kwargs.pop('user', None)
    parent = kwargs.pop('parent', None)