JAVA Object/String method overload [duplicate]

Answer 1

When you are doing method overloading, jvm tries to the next in hierarchy. For e.g. if you overload methods with long and int, but invoke method by passing byte, it will first go to int as it is next in hierarchy to byte.

Answer 2

Java Compiler chooses the most specific method.

String is a more specific type compared to the Object.

Answer 3

Whenever there's Method Overloading, the JVM will search for the method from the most specific type to least specific type

Answer 4

Becaue you are passing null in calling method and you defined void method(String str) And String always initlize with null. it will find that matching parametrized method. Thats y u got "str" on console.

Answer 5

It's because of method Overloading

The most specific method is chosen at compile time.

As 'java.lang.String' is a more specific type than 'java.lang.Object'. In your case it returns String.

Answer 6

See the JLS specification

15.12.2.5. Choosing the Most Specific Method

It is one of the puzzle of Java Puzzlers by Joshua Bloch - Puzzle 46: Case of the Confusing Constructor