Return local beginning of day time object

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天命终不由人
天命终不由人 2020-12-30 22:48

To get a local beginning of today time object I extract YMD and reconstruct the new date. That looks like a kludge. Do I miss some other standard library function?

c

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  • 2020-12-30 23:10

    EDIT: This only works for UTC times (it was tested in the playground, so the location-specific test was probably wrong). See PeterSO's answer for issues of this solution in location-specific scenarios.

    You can use the Truncate method on the date, with 24 * time.Hour as duration:

    http://play.golang.org/p/zJ8s9-6Pck

    func main() {
        // Test with a location works fine too
        loc, _ := time.LoadLocation("Europe/Berlin")
        t1, _ := time.ParseInLocation("2006 Jan 02 15:04:05 (MST)", "2012 Dec 07 03:15:30 (CEST)", loc)
        t2, _ := time.Parse("2006 Jan 02 15:04:05", "2012 Dec 07 00:00:00")
        t3, _ := time.Parse("2006 Jan 02 15:04:05", "2012 Dec 07 23:15:30")
        t4, _ := time.Parse("2006 Jan 02 15:04:05", "2012 Dec 07 23:59:59")
        t5, _ := time.Parse("2006 Jan 02 15:04:05", "2012 Dec 08 00:00:01")
        times := []time.Time{t1, t2, t3, t4, t5}
    
        for _, d := range times {
            fmt.Printf("%s\n", d.Truncate(24*time.Hour))
        }
    }
    

    To add some explanation, it works because truncate "rounds down to a multiple of" the specified duration since the zero time, and the zero time is January 1, year 1, 00:00:00. So truncating to the nearest 24-hour boundary always returns a "beginning of day".

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  • 2020-12-30 23:14

    Both the title and the text of the question asked for "a local [Chicago] beginning of today time." The Bod function in the question did that correctly. The accepted Truncate function claims to be a better solution, but it returns a different result; it doesn't return a local [Chicago] beginning of today time. For example,

    package main
    
    import (
        "fmt"
        "time"
    )
    
    func Bod(t time.Time) time.Time {
        year, month, day := t.Date()
        return time.Date(year, month, day, 0, 0, 0, 0, t.Location())
    }
    
    func Truncate(t time.Time) time.Time {
        return t.Truncate(24 * time.Hour)
    }
    
    func main() {
        chicago, err := time.LoadLocation("America/Chicago")
        if err != nil {
            fmt.Println(err)
            return
        }
        now := time.Now().In(chicago)
        fmt.Println(Bod(now))
        fmt.Println(Truncate(now))
    }
    

    Output:

    2014-08-11 00:00:00 -0400 EDT
    2014-08-11 20:00:00 -0400 EDT
    

    The time.Truncate method truncates UTC time.

    The accepted Truncate function also assumes that there are 24 hours in a day. Chicago has 23, 24, or 25 hours in a day.

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