Best and/or shortest way to do strict (non-type converting) <, >, <=, >= comparison in Javascript

Question

In Javascript, the == comparison has a strict (non-type converting) version: ===. Likewise, != has the strict form !==. T

Answer 1

How about creating a Object and using it

var strictComparison = {
    "<" : function(a,b) { return ((typeof a === typeof b) && (a < b)) },
    "<=" : function(a,b) { return ((typeof a === typeof b) && (a <= b)) },
    ">" : function(a,b) { return ((typeof a === typeof b) && (a > b)) },
    ">=" : function(a,b) { return ((typeof a === typeof b) && (a >= b)) }
};

console.log(strictComparison["<"](5,"6")) ;  
console.log(strictComparison[">"](5,6)) ;   

Answer 2

There are no built-in operators for what you want, but you can always create your own functions. For example, for <:

function lt(o1, o2) {
    return ((typeof o1 === typeof o2) && (o1 < o2));
}
lt("10", 11); // false

Another option, if you're only dealing with strings and numbers, is extending String.prototype and Number.prototype:

function lt(o) {
    return ((typeof this.valueOf() === typeof o) && (this < o));
}
String.prototype.lt = lt;
Number.prototype.lt = lt;
"10".lt(11);   // false
(11).lt("12"); // false