Is there a built-in way to convert IEnumerator
to IEnumerable
?
This is a variant I have written... The specific is a little different. I wanted to do a MoveNext()
on an IEnumerable<T>
, check the result, and then roll everything in a new IEnumerator<T>
that was "complete" (so that included even the element of the IEnumerable<T>
I had already extracted)
// Simple IEnumerable<T> that "uses" an IEnumerator<T> that has
// already received a MoveNext(). "eats" the first MoveNext()
// received, then continues normally. For shortness, both IEnumerable<T>
// and IEnumerator<T> are implemented by the same class. Note that if a
// second call to GetEnumerator() is done, the "real" IEnumerator<T> will
// be returned, not this proxy implementation.
public class EnumerableFromStartedEnumerator<T> : IEnumerable<T>, IEnumerator<T>
{
public readonly IEnumerator<T> Enumerator;
public readonly IEnumerable<T> Enumerable;
// Received by creator. Return value of MoveNext() done by caller
protected bool FirstMoveNextSuccessful { get; set; }
// The Enumerator can be "used" only once, then a new enumerator
// can be requested by Enumerable.GetEnumerator()
// (default = false)
protected bool Used { get; set; }
// The first MoveNext() has been already done (default = false)
protected bool DoneMoveNext { get; set; }
public EnumerableFromStartedEnumerator(IEnumerator<T> enumerator, bool firstMoveNextSuccessful, IEnumerable<T> enumerable)
{
Enumerator = enumerator;
FirstMoveNextSuccessful = firstMoveNextSuccessful;
Enumerable = enumerable;
}
public IEnumerator<T> GetEnumerator()
{
if (Used)
{
return Enumerable.GetEnumerator();
}
Used = true;
return this;
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
public T Current
{
get
{
// There are various school of though on what should
// happens if called before the first MoveNext() or
// after a MoveNext() returns false. We follow the
// "return default(TInner)" school of thought for the
// before first MoveNext() and the "whatever the
// Enumerator wants" for the after a MoveNext() returns
// false
if (!DoneMoveNext)
{
return default(T);
}
return Enumerator.Current;
}
}
public void Dispose()
{
Enumerator.Dispose();
}
object IEnumerator.Current
{
get
{
return Current;
}
}
public bool MoveNext()
{
if (!DoneMoveNext)
{
DoneMoveNext = true;
return FirstMoveNextSuccessful;
}
return Enumerator.MoveNext();
}
public void Reset()
{
// This will 99% throw :-) Not our problem.
Enumerator.Reset();
// So it is improbable we will arrive here
DoneMoveNext = true;
}
}
Use:
var enumerable = someCollection<T>;
var enumerator = enumerable.GetEnumerator();
bool res = enumerator.MoveNext();
// do whatever you want with res/enumerator.Current
var enumerable2 = new EnumerableFromStartedEnumerator<T>(enumerator, res, enumerable);
Now, the first GetEnumerator()
that will be requested to enumerable2
will be given through the enumerator enumerator
. From the second onward the enumerable.GetEnumerator()
will be used.
You could use the following which will kinda work.
public class FakeEnumerable<T> : IEnumerable<T> {
private IEnumerator<T> m_enumerator;
public FakeEnumerable(IEnumerator<T> e) {
m_enumerator = e;
}
public IEnumerator<T> GetEnumerator() {
return m_enumerator;
}
// Rest omitted
}
This will get you into trouble though when people expect successive calls to GetEnumerator to return different enumerators vs. the same one. But if it's a one time only use in a very constrained scenario, this could unblock you.
I do suggest though you try and not do this because I think eventually it will come back to haunt you.
A safer option is along the lines Jonathan suggested. You can expend the enumerator and create a List<T>
of the remaining items.
public static List<T> SaveRest<T>(this IEnumerator<T> e) {
var list = new List<T>();
while ( e.MoveNext() ) {
list.Add(e.Current);
}
return list;
}