An error when I add a variable to a string [duplicate]

Answer 1

This problem also arise when we don't give the single or double quotes to the database value.

Wrong way:

$query ="INSERT INTO tabel_name VALUE ($value1,$value2)";

As database inserting values must be in quotes ' '/" "

Right way:

$query ="INSERT INTO STUDENT VALUE ('$roll_no','$name','$class')";

Answer 2

You're missing your database name:

$sql = "SELECT ID, ListStID, ListEmail, Title FROM ".$entry_database." WHERE ID = ". $ReqBookID .";

And make sure that $entry_database isn't null or empty:

var_dump($entry_database);

Also notice that you don't need to have $ReqBookID in '' as if it's an Int.

Answer 3

You have empty $entry_database variable. As you see in error: ListEmail, Title FROM WHERE ID bewteen FROM and WHERE should be name of table. Proper syntax of SELECT:

SELECT columns FROM table [optional things as WHERE/ORDER/GROUP/JOIN etc]

which in your way should become:

SELECT ID, ListStID, ListEmail, Title FROM some_table_you_got WHERE ID = '4'