I have a batch script which will print the entire line of search string into a text file.
for %%i in (log.txt) do (
FINDSTR /G:pattern.txt %%i >> outpu
try this:
for /f "delims=:" %%a in ('findstr /in "error" log.txt') do set /a found=%%a
if not defined found (echo "error" not found&goto:eof)
set /a line1=found-1
set /a line2=found+1
for /f "tokens=1*delims=:" %%a in ('findstr /in "^" log.txt') do (
if %%a==%line1% >>output.txt echo(%%b
if %%a==%line2% >>output.txt echo(%%b
)
@echo off
setlocal EnableDelayedExpansion
rem Assemble the list of line numbers
set numbers=
for /F "delims=:" %%a in ('findstr /I /N /C:"error occurred" log.txt') do (
set /A before=%%a-1, after=%%a+1
set "numbers=!numbers!!before!: !after!: "
)
rem Search for the lines
(for /F "tokens=1* delims=:" %%a in ('findstr /N "^" log.txt ^| findstr /B "%numbers%"') do echo %%b) > output.txt
This uses a helper batch file called findrepl.bat from - http://www.dostips.com/forum/viewtopic.php?f=3&t=4697
@echo off
set "var=searchterm"
type "file.txt"|findrepl "%var%" /o:-1:+1 |find /v "%var%"