JavaScript - Compare two multidimensional arrays

Question

I have two multidimensional arrays:

first is something like ([\'one\',\'one\',\'three\'],[\'four\',\'five\',five\'],[\'one\',\'one\',\'one\'])

a

Answer 1

Possible duplicate of How to compare arrays in JavaScript?.

For a strict array comparison, check their length and values like so:

var a1 = [1, 2, 3];
var a2 = [1, 2, 3];

array_compare(a1, a2);

function array_compare(a1, a2) {
 if(a1.length != a2.length) {
  return false;
 }
 for(var i in a1) {
  // Don't forget to check for arrays in our arrays.
  if(a1[i] instanceof Array && a2[i] instanceof Array) {
   if(!array_compare(a1[i], a2[i])) {
    return false;
   }
  }
  else if(a1[i] != a2[i]) {
   return false;
  }
 }
 return true;
}

Answer 2

var md1 = [['one','one','three'],['four','five','five'],['one','one','one']];

var md2 = [['one','one','nine'],['one','one','one'],['two','two'],['two','two','two']];

//Iterate through all elements in first array
for(var x = 0; x < md1.length; x++){

    //Iterate through all elements in second array    
    for(var y = 0; y < md2.length; y++){

      /*This causes us to compare all elements 
         in first array to each element in second array
        Since md1[x] stays fixed while md2[y] iterates through second array.
         We compare the first two indexes of each array in conditional
      */
      if(md1[x][0] == md2[y][0] && md1[x][1] == md2[y][1]){
        alert("match found");
        alert("Array 1 element with index " + x + " matches Array 2 element with index " + y);
      }
    }
}

Working Example http://jsfiddle.net/2nxBb/1/