I\'m looking for a solution for a Java based webapplication to uniquely identify the client. The server is in the same network as the clients and I thought that using the MA
The best I could find is this: Query ARP cache to get MAC ID
And the potted summary is that:
I don't think this is a good approach for identifying your user's machine.
Consider also that:
Usage of IP address isn't working in the local network. I have used some other method to get a MAC address - sysout parsing of useful commands.
public String getMacAddress() throws Exception {
String macAddress = null;
String command = "ifconfig";
String osName = System.getProperty("os.name");
System.out.println("Operating System is " + osName);
if (osName.startsWith("Windows")) {
command = "ipconfig /all";
} else if (osName.startsWith("Linux") || osName.startsWith("Mac") || osName.startsWith("HP-UX")
|| osName.startsWith("NeXTStep") || osName.startsWith("Solaris") || osName.startsWith("SunOS")
|| osName.startsWith("FreeBSD") || osName.startsWith("NetBSD")) {
command = "ifconfig -a";
} else if (osName.startsWith("OpenBSD")) {
command = "netstat -in";
} else if (osName.startsWith("IRIX") || osName.startsWith("AIX") || osName.startsWith("Tru64")) {
command = "netstat -ia";
} else if (osName.startsWith("Caldera") || osName.startsWith("UnixWare") || osName.startsWith("OpenUNIX")) {
command = "ndstat";
} else {// Note: Unsupported system.
throw new Exception("The current operating system '" + osName + "' is not supported.");
}
Process pid = Runtime.getRuntime().exec(command);
BufferedReader in = new BufferedReader(new InputStreamReader(pid.getInputStream()));
Pattern p = Pattern.compile("([\\w]{1,2}(-|:)){5}[\\w]{1,2}");
while (true) {
String line = in.readLine();
System.out.println("line " + line);
if (line == null)
break;
Matcher m = p.matcher(line);
if (m.find()) {
macAddress = m.group();
break;
}
}
in.close();
return macAddress;
}
This should work everywhere. At least, the usage of this method on Ubuntu machine gives the following result:
Operating System is Linux
line eth0 Link encap:Ethernet HWaddr f4:6d:04:63:8e:21
mac: f4:6d:04:63:8e:21
I wrote my own method to solve my issue. Here it is if ever someone needs code to find a MAC address in the same network. Works for me without any admin privileges on Win 7 and Mac OS X 10.8.2
Pattern macpt = null;
private String getMac(String ip) {
// Find OS and set command according to OS
String OS = System.getProperty("os.name").toLowerCase();
String[] cmd;
if (OS.contains("win")) {
// Windows
macpt = Pattern
.compile("[0-9a-f]+-[0-9a-f]+-[0-9a-f]+-[0-9a-f]+-[0-9a-f]+-[0-9a-f]+");
String[] a = { "arp", "-a", ip };
cmd = a;
} else {
// Mac OS X, Linux
macpt = Pattern
.compile("[0-9a-f]+:[0-9a-f]+:[0-9a-f]+:[0-9a-f]+:[0-9a-f]+:[0-9a-f]+");
String[] a = { "arp", ip };
cmd = a;
}
try {
// Run command
Process p = Runtime.getRuntime().exec(cmd);
p.waitFor();
// read output with BufferedReader
BufferedReader reader = new BufferedReader(new InputStreamReader(
p.getInputStream()));
String line = reader.readLine();
// Loop trough lines
while (line != null) {
Matcher m = macpt.matcher(line);
// when Matcher finds a Line then return it as result
if (m.find()) {
System.out.println("Found");
System.out.println("MAC: " + m.group(0));
return m.group(0);
}
line = reader.readLine();
}
} catch (IOException e1) {
e1.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}
// Return empty string if no MAC is found
return "";
}