How can I select the record with the 2nd highest salary in database Oracle?

Question

Suppose I have a table employee with id, user_name, salary. How can I select the record with the 2nd highest salary in Oracle?

I googled it, find this solution, is t

Answer 1

If you're using Oracle 8+, you can use the RANK() or DENSE_RANK() functions like so

SELECT *
FROM (
  SELECT some_column, 
         rank() over (order by your_sort_column desc) as row_rank
) t
WHERE row_rank = 2;

Answer 2

You should use something like this:

SELECT *
FROM (select salary2.*, rownum rnum from
         (select * from salary ORDER BY salary_amount DESC) salary2
  where rownum <= 2 )
WHERE rnum >= 2;

Answer 3

select max(Salary) from EmployeeTest where Salary < ( select max(Salary) from EmployeeTest ) ;

this will work for all DBs.

Answer 4

I believe this will accomplish the same result, without a subquery or a ranking function:

SELECT *
FROM emp
ORDER BY sal DESC
LIMIT 1
OFFSET 2

Answer 5

You can use two max function. Let's say get data of userid=10 and its 2nd highest salary from SALARY_TBL.

select max(salary) from SALARY_TBL
where 
userid=10
salary <> (select max(salary) from SALARY_TBL where userid=10)

Answer 6

select salary from EmployeeDetails order by salary desc limit 1 offset (n-1).

If you want to find 2nd highest than replace n with that 2.