I have the following question. We have to pass callback functions to the C code. If the function is a Cython function in the same module, the situation is quite simple
In this example, extracted from a Python wrapper to the Cubature integration C library, a Python function is passed to a C function that has the prototype given by cfunction
. You can create a function with the same prototype, called cfunction_cb
(callback), and returning the same type, int
in this example):
cdef object f
ctypedef int (*cfunction) (double a, double b, double c, void *args)
cdef int cfunction_cb(double a, double b, double c, void *args):
global f
result_from_function = (<object>f)(a, b, c, *<tuple>args)
for k in range(fdim):
fval[k] = fval_buffer[k]
return 0
When calling the C function, you can cast your callback wrapper using the C prototype:
def main(pythonf, double a, double b, double c, args):
global f
f = pythonf
c_function( <cfunction> cfunction_cb,
double a,
double b,
double c,
<void *> args )
In this example it is also shown how to pass arguments to your Python function, through C.
I think the easiest way would be to wrap C callbacks in
cdef class Callback(object):
cdef int (*f)(int) # I hope I got the syntax right...
def __call__(int x):
return self.f(x)
so you can pass objects of this type, as well as any other callable, to the function that must call the callback.
However, if you must call the callback from C, then you should may pass it an extra argument, namely the optional address of a Python object, perhaps cast to `void*.
(Please do not cast function pointers to long
, or you may get undefined behavior. I'm not sure if you can safely cast a function pointer to anything, even void*
.)