I try to use stringr
package to extract part of a string, which is between two particular patterns.
For example, I have:
my.string <
I do not know whether and how this is possible with functions provided by stringr but you can also use base regexpr
and substring
:
pattern <- paste0("(?<=", left.border, ")[a-z]+(?=", right.border, ")")
# "(?<=nana)[a-z]+(?=baba)"
rx <- regexpr(pattern, text=my.string, perl=TRUE)
# [1] 5
# attr(,"match.length")
# [1] 6
substring(my.string, rx, rx+attr(rx, "match.length")-1)
# [1] "qwerty"
I would use str_match
from stringr: "str_match extracts capture groups formed by
() from the first match. It returns a character matrix with one column for the complete match and one column for each group." ref
str_match(my.string, paste(left.border, '(.+)', right.border, sep=''))[,2]
The code above creates a regular expression with paste
concatenating the capture group (.+)
that captures 1 or more characters, with left and right borders (no spaces between strings).
A single match is assumed. So, [,2]
selects the second column from the matrix returned by str_match
.
In base
R you can use gsub
. The parentheses in the pattern
create numbered capturing groups. Here we select the second group in the replacement
, i.e. the group between the borders. The .
matches any character. The *
means that there is zero or more of the preceeding element
gsub(pattern = "(.*nana)(.*)(baba.*)",
replacement = "\\2",
x = "xxxnanaRisnicebabayyy")
# "Risnice"
You can use the package unglue:
library(unglue)
my.string <- "nanaqwertybaba"
unglue_vec(my.string, "nana{res}baba")
#> [1] "qwerty"