This might be simple enough with basic SQL or it might need a REGEXP but I\'ve hit a brick wall.
My data is stored in a JSON string like these two examples (each in
In SQL it is really simple, because you only need to identify the last opening bracket. This can you do with substring index.
Maybe your table called test, and your field with the string called text - this should work
select text from (select substring_index(text,'[',-1) as text from test) as new where text like '%5%'**
If you have a text between 2 unique delimiters, maybe u find this tutorial helpful
I think I solved it by using this: AND extra_fields REGEXP '(.*"id":"2".*)("\[.*"1".*\]")'
. It's more to do with regular expressions than it is to do with MySQL :P
comment: (I couldn't find comment button)
This syntax becomes clearer when you learn that "extra_fields" is the name of the column in the table