How can I check if mysql table field even exists ?
The column name is \'price\' and I need to see if it exists.
Haven\'t understood really how the \'EXISTS\'
I just done something like this using this function for Wordpress, this for update tables that having new chnages on it
public function alterTable() {
$table_name = $this->prefix . $this->tables['name'];
$select = "select * from `{$table_name}` where 0=0 limit 1;";
$query = $this->db->get_results($select, ARRAY_A);
if (isset($query[0]) && !key_exists('adv', $query[0])) {
$sql = "ALTER TABLE `{$table_name}` ADD `me` INT NULL DEFAULT NULL ;";
$this->db->query($sql);
}
}
well here is a function to check out if a particular column exists or not.
public function detect_column($my_db, $table, $column)
{
$db = mysql_select_db($my_db); //select the database
$sql = "SHOW COLUMNS FROM $table LIKE '$column'"; //query
$result = mysql_query($sql); //querying
if(mysql_num_rows($result) == 0) //checks the absence of column
echo "column $column doesn't exist !";
// write your code here!
else
echo "column $column exists!";
}
well if you are designing a frame work, then this function may come to your aid. This function checks for the presence of column when $flag is set to '1' and absence of column when $flag is set to '0'.
public function detect_column($my_db, $table, $column, $flag)
{
$this->select_db($my_db); //select the database
$sql = "SHOW COLUMNS FROM $table LIKE '$column'";
$result = mysql_query($sql);
if(mysql_num_rows($result) == $flag)
return true;
else
return false;
}