Andrei Alexandrescu gave an excellent talk entitled: Variadic Templates are Funadic.
He presents the following 3 expansions which are subltey different:
#include <iostream>
#include <memory>
#include <typeinfo>
#include <cstdlib>
#include <cxxabi.h>
template <typename T>
std::unique_ptr<char, void(*)(void*)>
type_name()
{
return std::unique_ptr<char, void(*)(void*)>
(
__cxxabiv1::__cxa_demangle(typeid(T).name(), nullptr,
nullptr, nullptr),
std::free
);
}
void display() {}
template <class T>
void
display()
{
std::cout << type_name<T>().get() << ' ';
}
template <class T, class T2, class ...Tail>
void
display()
{
std::cout << type_name<T>().get() << ' ';
display<T2, Tail...>();
}
template <class... Ts>
struct A
{
template <class... Us>
static
int
hun(Us... us)
{
std::cout << "A<";
display<Ts...>();
std::cout << ">::hun(";
display<Us...>();
std::cout << ")\n";
return 0;
}
};
template <class ...T>
void gun(T...) {}
template <class... Ts> void fun( Ts... vs )
{
std::cout << "gun( A<Ts...>::hun(vs)...);\n";
gun( A<Ts...>::hun(vs)...);
std::cout << "\ngun( A<Ts...>::hun(vs...));\n";
gun( A<Ts...>::hun(vs...));
std::cout << "\ngun( A<Ts>::hun(vs)...);\n";
gun( A<Ts>::hun(vs)...);
}
int main()
{
fun(1, 'a', 2.3);
}
Output:
gun( A<Ts...>::hun(vs)...);
A<int char double >::hun(int )
A<int char double >::hun(char )
A<int char double >::hun(double )
gun( A<Ts...>::hun(vs...));
A<int char double >::hun(int char double )
gun( A<Ts>::hun(vs)...);
A<int >::hun(int )
A<char >::hun(char )
A<double >::hun(double )
Cases 2 and 3 really are very common in any kind of code involving variadic packs.
template<typename... T>
void f(T&&... t)
{
// Case 2:
auto t2 = std::tuple<T...>(t...);
// Case 3:
auto t3 = std::make_tuple(std::forward<T>(t)...);
}
Looking at my own code, I can't find any surviving example of case 1. I may have used it in the past in some detail
namespace for a helper tempate, but I'm not sure. I don't think it's going to be common or even necessary most of the time.