PHP preg_replace three times with three different patterns? right or wrong?

Question

A simple question: Is this the best way to do it?

$pattern1 = \"regexp1\";
$pattern2 = \"regexp2\";
$pattern3 = \"regexp3\";

$content = preg_replace($patter         


        

Answer 1

I am using it for XML tags string.

<?php 

 $string = '<JUDGE_NAME><NAME>Ahmad Maarop</NAME>CJ, <NAME>Zaharah Ibrahim</NAME>, <NAME>Prasad Sandosham</NAME>, <NAME>Jeffrey Tan</NAME>, <NAME>Alizatul Khair</NAME> FCJJ</JUDGE_NAME>\r\n';
 $patterns = array('/\bCJ\b/', '/\bJCA\b/','/\bJJCA\b/','/\bPCA\b/', '/\bCJM\b/', '/\bCJSS\b/', '/\bFCJ\b/', '/\bFCJJ\b/', '/\bJ\b/','/\bH\b/', '/\bPK\b/','/\bJC\b/', '/\bHMP\b/', '/\bHHMP\b/', '/\bHMR\b/', '/\bHHMR\b/');
 $replacements = array('<rank>CJ</rank>', '<rank>JCA</rank>','<rank>JJCA</rank>','<rank>PCA</rank>', '<rank>CJM</rank>', '<rank>CJSS</rank>', '<rank>FCJ</rank>', '<rank>FCJJ</rank>', '<rank>J</rank>','<rank>H</rank>', '<rank>PK</rank>','<rank>JC</rank>', '<rank>HMP</rank>', '<rank>HHMP</rank>', '<rank>HMR</rank>', '<rank>HHMR</rank>');

   


  $string = preg_replace($patterns,$replacements,$xmlString);
  
  
  echo $string;
// <JUDGE_NAME><NAME>Ahmad Maarop</NAME> <rank>CJ</rank>, <NAME>Zaharah Ibrahim</NAME>, <NAME>Prasad Sandosham</NAME>, <NAME>Jeffrey Tan</NAME>, <NAME>Alizatul Khair</NAME> <rank>FCJJ</rank></JUDGE_NAME>\r\n ◀

  
?>

Answer 2

hope this example helping you to understand "find in array", and "replace from array"

$pattern=array('1','2','3');
$replace=array('one','two','tree');
$content = preg_replace($pattern,$replace, $content);

Answer 3

As you are replacing all with the same, you could do either pass an array

$content = preg_replace(array($pattern1,$pattern2, $pattern3), '', $content);

or create one expression:

$content = preg_replace('/regexp1|regexp2|regexp3/', '', $content);

---

If the "expressions" are actually pure character strings, use str_replace instead.

Answer 4

A very readable approach is to make an array with patterns and replacements, and then use array_keys and array_values in the preg_replace

$replace = [
   "1" => "one",
   "2" => "two",
   "3" => "three"
];
$content = preg_replace( array_keys( $replace ), array_values( $replace ), $content );

This even works with more complex patterns. The following code will replace 1, 2 and 3, and it will remove double spaces.

$replace = [
   "1"       => "one",
   "2"       => "two",
   "3"       => "three",
   "/ {2,}/" => " "
];
$content = preg_replace( array_keys( $replace ), array_values( $replace ), $content );

Answer 5

To do multiple searches in a single preg_replace() call, use an array of patterns. You can still pass a single replacement, this is what's matched by all three patterns is replaced with:

$content = preg_replace(array($pattern1, $pattern2, $pattern3), '', $content);