Does a Python object which doesn't override comparison operators equals itself?

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独厮守ぢ 2020-12-30 06:21
class A(object):

    def __init__(self, value):
        self.value = value

x = A(1)
y = A(2)

q = [x, y]
q.remove(y)

I want to remove from the li

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  • 2020-12-30 07:03

    In python, by default an object is always equal to itself (the only exception I can think of is float("nan"). An object of a user-defined class will not be equal to any other object unless you define a comparison function.

    See also http://docs.python.org/reference/expressions.html#notin

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  • 2020-12-30 07:07

    Yes. In your example q.remove(y) would remove the first occurrence of an object which compares equal with y. However, the way the class A is defined, you shouldn't ever have a variable compare equal with y - with the exception of any other names which are also bound to the same y instance.

    The relevant section of the docs is here:

    If no __cmp__(), __eq__() or __ne__() operation is defined, class instances are compared by object identity ("address").

    So comparison for A instances is by identity (implemented as memory address in CPython). No other object can have an identity equal to id(y) within y's lifetime, i.e. for as long as you hold a reference to y (which you must, if you're going to remove it from a list!)

    Technically, it is still possible to have objects at other memory locations which are comparing equal - mock.ANY is one such example. But these objects need to override their comparison operators to force the result.

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  • 2020-12-30 07:22

    The answer is yes and no.

    Consider the following example

    >>> class A(object):
        def __init__(self, value):
            self.value = value        
    >>> x = A(1)
    >>> y = A(2)
    >>> z = A(3)
    >>> w = A(3)
    >>> q = [x, y,z]
    >>> id(y) #Second element in the list and y has the same reference
    46167248
    >>> id(q[1]) #Second element in the list and y has the same reference
    46167248
    >>> q.remove(y) #So it just compares the id and removes it
    >>> q
    [<__main__.A object at 0x02C19AB0>, <__main__.A object at 0x02C19B50>]
    >>> q.remove(w) #Fails because though z and w contain the same value yet they are different object
    Traceback (most recent call last):
      File "<pyshell#11>", line 1, in <module>
        q.remove(w)
    ValueError: list.remove(x): x not in list 
    

    It will remove from the list iff they are the same object. If they are different object with same value it won;t remove it.

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