class A(object):
def __init__(self, value):
self.value = value
x = A(1)
y = A(2)
q = [x, y]
q.remove(y)
I want to remove from the li
In python, by default an object is always equal to itself (the only exception I can think of is float("nan")
. An object of a user-defined class will not be equal to any other object unless you define a comparison function.
See also http://docs.python.org/reference/expressions.html#notin
Yes. In your example q.remove(y)
would remove the first occurrence of an object which compares equal with y
. However, the way the class A
is defined, you shouldn't† ever have a variable compare equal with y
- with the exception of any other names which are also bound to the same y
instance.
The relevant section of the docs is here:
If no
__cmp__(), __eq__() or __ne__()
operation is defined, class instances are compared by object identity ("address").
So comparison for A
instances is by identity (implemented as memory address in CPython). No other object can have an identity equal to id(y)
within y
's lifetime, i.e. for as long as you hold a reference to y
(which you must, if you're going to remove it from a list!)
† Technically, it is still possible to have objects at other memory locations which are comparing equal - mock.ANY
is one such example. But these objects need to override their comparison operators to force the result.
The answer is yes and no.
Consider the following example
>>> class A(object):
def __init__(self, value):
self.value = value
>>> x = A(1)
>>> y = A(2)
>>> z = A(3)
>>> w = A(3)
>>> q = [x, y,z]
>>> id(y) #Second element in the list and y has the same reference
46167248
>>> id(q[1]) #Second element in the list and y has the same reference
46167248
>>> q.remove(y) #So it just compares the id and removes it
>>> q
[<__main__.A object at 0x02C19AB0>, <__main__.A object at 0x02C19B50>]
>>> q.remove(w) #Fails because though z and w contain the same value yet they are different object
Traceback (most recent call last):
File "<pyshell#11>", line 1, in <module>
q.remove(w)
ValueError: list.remove(x): x not in list
It will remove from the list iff they are the same object. If they are different object with same value it won;t remove it.