Exception in thread “main” java.lang.NumberFormatException: For input string: “S” [closed]

Answer 1

yes of course.. Integer.parseInt can make the integer representation of only numeric strings.Try:

String s="98"

Answer 2

it is nothing to do with single or multichar value. A simple test of this is that, if you remove the ' (quotes) from the value, would you find a Integer?

If no, the Integer.parseiInt() is bound to fail.

I would recomend you to go for really quick and short tutorial located at http://www.tutorialspoint.com/java/number_parseint.htm

Answer 3

The letter S is not a number. Did you mean to write the number 5?

String s = "5";
System.out.println((char) Integer.parseInt(s));

Or did you mean to print the ASCII or Unicode value of the character S?

char s = 's';
System.out.println((int) s);

Answer 4

To parse an string to a number you must have valid number into the string.

Here your S is not a number.

String s = "s"; System.out.println((char) Integer.parseInt(s));

It should be something like this:

String s = "100";//or whatever integer you want to parse.
System.out.println((char) Integer.parseInt(s));

Answer 5

parseInt(String s) is used to convert integers in string form like "42" to value they represent in decimal. Use String.charAt(0) if you want first character.