This will remove the x namespace from output.
<xsl:namespace-alias result-prefix="#default" stylesheet-prefix="x" />
Remember to do two things when you deal with a default namespace. First map it into something in the stylesheet tag, and then remove it using a namespace-alias.
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:x="http://tempuri.com"
exclude-result-prefixes="x"
>
<!-- the identity template copies everything 1:1 -->
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()" />
</xsl:copy>
</xsl:template>
<!-- this template explicitly cares for namespace'd attributes -->
<xsl:template match="@x:*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="." />
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:x="http://tempuri.com">
<xsl:template match="/">
<xsl:apply-templates select="/a/b"/>
</xsl:template>
<xsl:template match="*">
<xsl:element name="{local-name(.)}">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="@*">
<xsl:copy/>
</xsl:template>
<!-- This empty template is not needed.
Neither is the xmlns declaration above:
<xsl:template match="@x:*"/> -->
</xsl:stylesheet>
I found an explanation here.
Michael Kay wrote:
exclude-result-prefixes only affects the namespaces copied from the stylesheet by a literal result element, it doesn't affect copying of namespaces from source documents.
Try this (note the attribute copy-namespaces='no'
):
<xsl:template match="node()">
<xsl:copy copy-namespaces="no">
<xsl:apply-templates select="node()"/>
</xsl:copy>
</xsl:template>