An Url, Credentials works in RestClient UI as well as with Curl where as i\'m getting \"500\" error when access the same via Spring RestTemplate.
I am using the foll
Below works fine
For Post:
restTemplate.postForObject(url, parametersMap, Employee.class);
url is : String - rest api URL parametersMap - MultiValueMap Employee - object which needs to be converted from the JSON response
Though its too late to answer, below solution will help someone if above solutions did not work. For me, the error was with Request object and its header. Your request object should generate JSON as required by api. It should not have any extra field or additional getter method. In my case, I had additional getter method which was adding unnecessary field to request
postForEntity = restTemplate.postForEntity(uri,entity,String.class);
I have also faced a situation where server response was "500 Internal server error"
Though I have received success response from Postman for the same parameter value. So the problem was not in server side.
The problem was typo in parameter name, mismatch spelling between application parameter and server parameter
Server parameter -> requestLabel
Application parameter -> requestLable
Hope someone new like me get help from this.
I would suggest to create your HttpComponentsClientHttpRequestFactory
and pass it to your RestTemplate
as described below:
ClientHttpRequestFactory requestFactory = new
HttpComponentsClientHttpRequestFactory(HttpClients.createDefault());
RestTemplate restTemplate = new RestTemplate(requestFactory);
By this way, you would avoid server-side issues (like facing error code 500) when testing your application.
I had the same issue that worked in my local environment and not on the server.
It is a good practice to pass HttpClients.createDefault()
to your HttpComponentsClientHttpRequestFactory
while constructing it since by default, this factory uses system properties to create HttpClient
for your factory and that may cause lots of pain in real server environment. You may also pass your custom HttpClient
.
You are passing name and password as uri variable:
public <T> T postForObject(java.lang.String url,
@Nullable
java.lang.Object request,
java.lang.Class<T> responseType,
java.util.Map<java.lang.String,?> uriVariables)
throws RestClientException
docs.spring.io
If you had some url like: http://yourhost:8080/dosomethingwithemployee/name/password and you extracted name&password from url itself, then it probably would work.
String url = "http://yourhost:8080/dosomethingwithemployee/{name}/{password}"
restTemplate.postForObject(url, request, Employee.class, map);
However, I think you have been trying to send name and password in request body:
public SomeType getResponse(String login, String password) {
MultiValueMap<String, String> headers = new LinkedMultiValueMap<>();
headers.add("Content-Type", "application/json");
Employee employee = new Employee();
employee.setName(login);
employee.setPassword(password);
SomeType responseBody = post("http://locahost:8080/dosomethingwithemployee", employee, headers, SomeType.class);
return responseBody;
}
public <T> T post(String url, Object requestObject, MultiValueMap<String, String> headers, Class<T> responseType) {
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
restTemplate.getMessageConverters().add(new StringHttpMessageConverter());
HttpEntity request = new HttpEntity(requestObject, headers);
T responseObject = restTemplate.postForObject(url, request, responseType);
return responseObject;
}
RestTemplate header Accept problem
--> accept - text/plain, application/json, */*
HttpClient 4.x header Accept
--> accept - application/json
so i fixed
HttpHeaders headers = new HttpHeaders();
headers.add("Accept", MediaType.APPLICATION_JSON_VALUE);
http://www.manning-sandbox.com/message.jspa?messageID=119733