Iterate through alphabet in Swift

Question

in Obj-C it was possible to iterate through alphabet with:

for (char x=\'A\'; x<=\'Z\'; x++) {

In Swift this isn\'t possible. Any idea h

Answer 1

Updated for Swift 3.0 and higher

let startChar = Unicode.Scalar("A").value
let endChar = Unicode.Scalar("Z").value

for alphabet in startChar...endChar {

    if let char = Unicode.Scalar(alphabet) {

        print(char)
    }
}

Answer 2

for i in 97...122{println(UnicodeScalar(i))}

Answer 3

Swift 4.2 version is much easier

for char in "abcdefghijklmnopqrstuvwxyz" {
    print(char)
}

Answer 4

Did you try this one ?

for var myChar:CChar = 65 ; myChar <= 90 ; ++myChar {
      let x:String = String(format: "%c", myChar)
      println(x)
}

If you already know the character code

Answer 5

It's slightly cumbersome, but the following works (Swift 3/4):

for value in UnicodeScalar("a").value...UnicodeScalar("z").value { print(UnicodeScalar(value)!) }

I suspect that the problem here is that the meaning of "a"..."z" could potentially be different for different string encodings.

---

(Older stuff)

Also cumbersome, but without the extra intermediate variable:

    for letter in map(UnicodeScalar("a").value...UnicodeScalar("z").value, {(val: UInt32) -> UnicodeScalar in return UnicodeScalar(val); })
    {
        println(letter)
    }

Answer 6

"Pure functional" Swift 5 way:

(Unicode.Scalar("A").value...Unicode.Scalar("Z").value).forEach({
    let letter = Unicode.Scalar($0)!
    print(letter)
    /* do other stuff with letter here */
})