How do I compare two variables containing strings in JavaScript?

Question

I want compare two variables, that are strings, but I am getting an error.

Answer 1

instead of using the == sign, more safer use the === sign when compare, the code that you post is work well

Answer 2

I used below function to compare two strings and It is working good.

function CompareUserId (first, second)
{

   var regex = new RegExp('^' + first+ '$', 'i');
   if (regex.test(second)) 
   {
        return true;
   }
   else 
   {
        return false;
   }
   return false;
}

Answer 3

=== is not necessary. You know both values are strings so you dont need to compare types.

function do_check()
{
  var str1 = $("#textbox1").val();
  var str2 = $("#textbox2").val();

  if (str1 == str2)
  {
    $(":text").removeClass("incorrect");
    alert("equal");
  }
  else
  {
    $(":text").addClass("incorrect");
    alert("not equal");
  }
}

.incorrect
{
  background: #ff8888;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<input id="textbox1" type="text">
<input id="textbox2" type="text">

<button onclick="do_check()">check</button>

Answer 4

You can use javascript dedicate string compare method string1.localeCompare(string2). it will five you -1 if the string not equals, 0 for strings equal and 1 if string1 is sorted after string2.

<script>
    var to_check=$(this).val();
    var cur_string=$("#0").text();
    var to_chk = "that";
    var cur_str= "that";
    if(to_chk.localeCompare(cur_str) == 0){
        alert("both are equal");
        $("#0").attr("class","correct");    
    } else {
        alert("both are not equal");
        $("#0").attr("class","incorrect");
    }
</script>