Determine if string is all caps with regular expression

Question

How can you determine if a string is all caps with a regular expression. It can include punctuation and numbers, just no lower case letters.

Answer 1

Why not just use if(string.toUpperCase() == string)? ._. Its more "elegant"...
I think you're trying to force in RegExp, but as someone else stated, I don't think this is the best use of regexp...

Answer 2

Simplest would seem to be:

^[^a-z]*$

Answer 3

How about (s == uppercase(s)) --> string is all caps?

Answer 4

The string contains a lowercase letter if the expression /[a-z]/ returns true, so simply perform this check, if it's false you have no lowercase letters.

Answer 5

That sounds like you want: ^[^a-z]*$

Answer 6

m/^[^a-z]*$/

For non-English characters,

m/^\P{Ll}*$/

(\P{Ll} is the same as [^\p{Ll}], which accepts all characters except the ones marked as lower-case.)