Sorting a dictionary (with date keys) in Python

Question

I have a dictionary. The keys are dates (datetime). I need to sort the dictionary so that the values in the dictionary are sorted by date - so that by iterating through the

Answer 1

Dictionaries are unsortable. Iterate over sorted(mydict.keys()) instead.

Answer 2

Python 2.7 (released on July 3rd, 2010) supports an ordered dictionary type:

http://www.python.org/download/releases/2.7/

Answer 3

I'm sure that python knows how to compare dates. So:

def sortedDictValues(adict):
 items = adict.items()
 items.sort()
 return [value for key, value in items]

Answer 4

Dictionaries never store anything in some order. But you can get a list of keys using d.keys() which could be sorted. Iterate over a generator like below.

def sortdict(d):
    for key in sorted(d): yield d[key]

Using this you will be able to iterate over values in chronological order.

for value in sortdict(mydict):
    # your code
    pass

Answer 5

since your date strings seem to be in a proper format you could just do:

>>> sorted(mydict.items())         # iteritems in py2k
[('2000-01-01', {'fld_2': 42, 'fld_1': 1}), ('2000-01-02', {'fld_2': 22.17, 'fld_1': 23})]

Answer 6

If you're using Python 2.7+ or 3.1+ you could create an OrderedDict from collections from a sort of your dictionary and then iterate through that.

from collections import OrderedDict

ordered = OrderedDict(sorted(mydict.items(), key=lambda t: t[0]))

However, depending on what you want to do it's probably easier to iterate over a sorted list of keys from your dict.