Throwing out of range exception in C++

Question

This code works;

int at(int index) {
  if(index < 1 || index >= size)
    throw 0;

  return x[index];
}

Yet this doesn\'t

Answer 1

Replace throw std::out_of_range; with throw std::out_of_range ("blah");. I.e. you need to create an object, you cannot throw a type.