Is there a way in jQuery to bring a div to front?

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渐次进展 2020-12-29 20:42

If I had a bunch of absolute positioned divs and they overlapped, how would I get a certain div to come to the front? Thanks again guys!

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  • 2020-12-29 20:59

    When you are working with multiple elements you'll have to loop through and see which has the highest z-index, and set the top to that+1.

    http://jsfiddle.net/forresto/Txh7R/

    var topZ = 0;
    $('.class-to-check').each(function(){
      var thisZ = parseInt($(this).css('zIndex'), 10);
      if (thisZ > topZ){
        topZ = thisZ;
      }
    });
    $('.clicked-element').css('zIndex', topZ+1);
    

    For a non-CSS version (if none of the layers have z-index specified) you can also just append the element again:

    $('.click-to-top').click(function(){
      $(this).parent().append(this);
    });
    

    (I don't know if that is slower than with CSS z-index.)

    For non-CSS non-jQuery, just append it again:

    // var element = document...;
    element.parentNode.appendChild(element);
    
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  • 2020-12-29 21:00

    It would be overkill to use jQuery for this. Instead use CSS' z-index property:

    <style type="text/css">
      #myElement {
        z-index: 50000;
      }
    </style>
    
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  • 2020-12-29 21:01

    With jQuery (like you asked):

    $('#a-div').parent().append($('#a-div')); // Pop a div to the front
    

    Weird how everyone went with z-index. Why override natural stacking order when you can just pop it to the front within the DOM?

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  • 2020-12-29 21:09

    This is a CSS thing, not a jQuery thing (though you can use jQuery to modify the css).

    $('element').css('z-index', 9999);  // note: it appears 'zIndex' no longer works
    

    Or, absolute positioning will bring something to the top:

    $('element').css('position', 'absolute');
    
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  • 2020-12-29 21:12
    element.style.zIndex = Date.now();
    
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  • 2020-12-29 21:13

    Use .css() and apply position attribute and z-index attribute.

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