Pythonic solution for conditional arguments passing

Question

I have a function with two optional parameters:

def func(a=0, b=10):
    return a+b

Somewhere else in my code I am doing some conditional a

Answer 1

You can use the ternary if-then operator to pass conditional arguements into functions https://www.geeksforgeeks.org/ternary-operator-in-python/

For example, if you want to check if a key actually exists before passing it you can do something like:

 
    def func(arg):
        print(arg)

    kwargs = {'name':'Adam')

    func( kwargs['name'] if 'name' in kwargs.keys() else '' )       #Expected Output: 'Adam'
    func( kwargs['notakey'] if 'notakey' in kwargs.keys() else '' ) #Expected Output: ''
 

Answer 2

You can add a decorator that would eliminate None arguments:

def skip_nones(fun):
    def _(*args, **kwargs):
        for a, v in zip(fun.__code__.co_varnames, args):
            if v is not None:
                kwargs[a] = v
        return fun(**kwargs)
    return _

@skip_nones
def func(a=10, b=20):
    print a, b

func(None, None) # 10 20
func(11, None)   # 11 20
func(None, 33)   # 10 33

Answer 3

To answer your literal question:

func(a or 0, b or 10) 

Edit: See comment why this doesn't answer the question.