How to ignore first element in xpath

Question

How can I ignore first element and get rest of the elements?

  
some link
  


        

Answer 1

if you want to ignore the "first" element only then:

//li[position()>1]
or
(//a)[position()>1] 

if you want the last only (like your example seems to suggest):

//li[last()]
or
(//a)[last()]

Answer 2

You can use position() to skip over the "first" one, but depending on which element you are interested in and what the context is, you may need a slight variation on your XPATH.

For instance, if you wanted to address all of the li elements and get all except the first, you could use:

//li[position()>1]

and it would work as expected, returning all of the li elements except for the first.

However, if you wanted to address all of the a elements you need to modify the XPATH slightly. In the context of the expression //a[position()>1] each one of the a elements will have a position() of 1 and last() will evaluate to true. So, it would always return every a and would not skip over the first one.

You need to wrap the expression that selects the a in parenthesis to group them in a node-set, then apply the predicate filter on position.

(//a)[position()>1]

Alternatively, you could also use an expression like this:

//a[preceding::a]

That will find all a elements except the first one (since there is no a preceding the first one).